Question

$cot\theta +tan\theta =$

• A. $\frac{1}{sin\theta cos\theta }$
• B. $sec\theta cosec\theta$
• C. $cot\theta se{c}^2\theta$
• D. all of these

Answer 1

The correct option is D all of these

A)

$\cot \theta +\tan \theta$

$=\frac{\cos \theta }{\sin \theta }+\frac{\sin \theta }{\cos \theta }$

$=\frac{{\cos }^2\theta +{\sin }^2\theta }{\sin \theta \cos \theta }$

$=\frac{1}{\sin \theta \cos \theta }$

B)

$cosec\theta \sec \theta$$=\frac{1}{\sin \theta \cos \theta }$

C)

$\cot \theta {\sec }^2\theta$

$=\frac{\cos \theta }{\sin \theta }\times \frac{1}{{\cos }^2\theta }=\frac{1}{\sin \theta \cos \theta }$.