Question

Counting by twos complete the series

$4,22,701;4,22,703;\_\_\_\_;\_\_\_;\_\_\_\_$

Answer 1

Given first two terms are

$4,22,701;4,22,703$

In these two terms the difference is $2$ i.e.,

$4,22,701+2=4,22,703$

To get the next term again add $2$ to $4,22,703$ i.e.,

$4,22,703+2=4,22,705$

To get the next term again add $2$ to $4,22,705$ i.e.,

$4,22,705+2=4,22,707$

To get the next term again add $2$ to $4,22,707$ i.e.,

$4,22,707+2=4,22,709$

Hence, the correct answer is $4,22,705;4,22,707;4,22,709$