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Hydrogen Bonding

Covalent bond...

Question

Covalent bond length of chlorine molecule is $1.98 A^{\circ}$ . Then covalent radius of chlorine is

A

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B

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C

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D

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Solution

The correct option is C
$C o v . r a d i u s = \frac{b o n d l e n g t h}{2} = \frac{1.98 A^{\circ}}{2} = 0.99 A^{\circ}$

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