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Question
Covalent radius of nitrogen is 70 pm. Hence, covalent radius of boron is about :
Covalent radius of nitrogen is 70 pm. Hence, covalent radius of boron is about :
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Solution
The correct option is C 110 pm
As we move along a period radius decreases and as we move down the group, radius increases.
Hence, B(5)>C(6)>N(7).
Also,
(rn∝1Z along a period).
As we move along a period radius decreases and as we move down the group, radius increases.
Hence, B(5)>C(6)>N(7).
Also,
(rn∝1Z along a period).
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