Question

CP: Given position time graph of a particles motion along x-axis

Q: At what time t is the particle moving towards the starting point?

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

At $t_a$, and $t_c$ the particles displacement is increasing with time.

Also the slope at $t_a$, and $t_c$, is positive which implies its velocity is positive. If velocity is positive the particle is going away from the starting point.
At t = $t_d$ the slope of graph is 0. So velocity is 0. Hence the particle is momentarily at rest.

$Att=t_e$ the slope of the particle is negative.

slope =tan$\theta$ $\because$ $\theta$ is obtuse

so tan $\theta$ =negative

so velocity is negative

Hence the particle is coming back to origin