${C r}_{2} O_{7}^{2 -} + {F e}^{2 +} ⟶ {F e}^{3 +} + {C r}^{3 +}$ (in acid solution)
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Solution

The correct option is A 1
The balanced redox reaction is as follows:
${C r}_{2} O_{7}^{2 -} + 14 H^{\oplus} + 6 {F e}^{2 +} ⟶ 2 {C r}^{3 +} + 7 H_{2} + 6 {F e}^{3 +}$

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Similar questions

{F e}^{2 +} (a q) + {C r}_{2} O_{7}^{2 -} (a q) (acid medium) - ------- \to {F e}^{3 +} (a q) + {C r}^{3 +} (a q)

{C r}_{2} O_{7}^{2 -} + {F e}^{2 +} + H^{\oplus} ⟶ {C r}^{3 +} + {F e}^{3 +} + H_{2} O

6 {F e}^{2 +} + 14 H^{\oplus} + {C r}_{2} O_{7}^{2 -} ⟶ 6 {F e}^{3 +} + 2 {C r}^{3 +} + 7 H_{2} O

{C r}_{2} O_{7}^{2 -} + {F e}^{2 +} ⟶ {F e}^{3 +} + {C r}^{3 +}

C r_{2} O_{7}^{2 -}

{F e}^{+ 2}

H_{2} O_{2} (a q) + {C r}_{2} O_{7}^{2 -} ⟶ O_{2} (g) + {C r}^{3 +} (a q)

{C r}_{2} O_{7}^{2 -}

{C r}^{3 +}

{C r}_{2} O_{7}^{2 -} = x \times

x

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