Cr 2 O 7 2- Cr- Eq-wt of Cr 2 O 7 2- is

The correct option is A mol.wt 6 Cr _ 2 O _ 7 ^ 2 +14 H ^ + +6e⟶ 2 Cr ^ 3+ +7 H _ 2 O ∴ Equivalent wt. of Cr _ 2 O _ 7 ^ 2 = mol.wt ...

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Byju's Answer

Standard XII

Chemistry

Stoichiometric Calculations

Cr 2 O 7 2- C...

Question

${C r}_{2} O_{7}^{2 -} H^{+} - - \to C r$ . Eq.wt of ${C r}_{2} O_{7}^{2 -}$ is

\frac{m o l . w t}{6}

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\frac{m o l . w t}{3}

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\frac{m o l . w t}{4}

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\frac{m o l . w t}{1}

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Solution

The correct option is A $\frac{m o l . w t}{6}$
${C r}_{2} O_{7}^{2 -} + 14 H^{+} + 6 e ⟶ 2 {C r}^{3 +} + 7 H_{2} O$
$∴$ Equivalent wt. of ${C r}_{2} O_{7}^{2 -} = \frac{m o l . w t}{6}$

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Cr2O2−7H+−−→Cr. Eq.wt of Cr2O2−7 is

The correct option is A mol.wt6Cr2O2−7+14H++6e⟶2Cr3++7H2O∴ Equivalent wt. of Cr2O2−7=mol.wt6

${C r}_{2} O_{7}^{2 -} H^{+} - - \to C r$ . Eq.wt of ${C r}_{2} O_{7}^{2 -}$ is

The correct option is A $\frac{m o l . w t}{6}$
${C r}_{2} O_{7}^{2 -} + 14 H^{+} + 6 e ⟶ 2 {C r}^{3 +} + 7 H_{2} O$
$∴$ Equivalent wt. of ${C r}_{2} O_{7}^{2 -} = \frac{m o l . w t}{6}$