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Byju's Answer
Standard XII
Chemistry
Oxidising Reagent and Reducing Reagent
Cr2O72-+4H2O2...
Question
C
r
2
O
2
−
7
+
4
H
2
O
2
+
2
H
+
o
r
g
a
n
i
c
−
−−−
→
s
o
l
v
e
n
t
X
+
5
H
2
O
Find the value of magnetic moment of X.
A
0
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B
√
3
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C
√
1
5
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D
√
8
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Solution
The correct option is
A
0
C
r
2
O
2
−
7
+
4
H
2
O
2
+
2
H
+
o
r
g
a
n
i
c
−
−−−
→
s
o
l
v
e
n
t
C
r
O
5
+
5
H
2
O
here in
C
r
O
5
Cr shows +6 oxidation state (
d
0
s
0
)
Thuse there are no unpaired electrons.
so value of magnetic moment
μ
=
0
Suggest Corrections
0
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