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Question

Cr2O2−7+4H2O2+2H+organic−−−−→solventX+5H2O

How many peroxy linkage(s) is/ are present in X?

A
3
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B
0
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C
1
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D
2
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Solution

The correct option is A 2
Cr2O27+4H2O2+2H+organic−−−solventCrO5+5H2O
and CrO5 have 2 peroxy linkage.

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