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Byju's Answer
Standard XII
Chemistry
Ion Electron Method
Cr2O72- + Fe2...
Question
C
r
2
O
2
−
7
+
F
e
2
+
+
H
+
→
C
r
3
+
+
F
e
3
+
+
H
2
O
Complete the reaction.
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Solution
At cathode
C
r
2
O
7
2
−
+
14
H
+
+
6
e
−
→
2
c
r
3
+
+
7
H
2
O
At anode
F
e
2
+
→
F
e
3
+
+
e
−
C
r
2
O
7
2
−
+
6
F
e
2
+
+
14
H
+
→
2
C
r
3
+
+
F
e
3
+
+
7
H
2
O
C
r
2
O
7
2
−
undergo reduction at cathode while
F
e
2
+
converted to
F
e
3
+
(oxidation ) occur at anode this is redox reaction..
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Similar questions
Q.
Balance the following ionic equations
(i)
C
r
2
O
2
−
7
+
H
+
+
I
−
→
C
r
3
+
+
I
2
+
H
2
O
(ii)
C
r
2
O
2
−
7
+
F
e
+
2
+
H
+
→
C
r
3
+
+
F
e
3
+
+
H
2
O
(iii)
M
n
O
4
−
+
S
O
2
−
3
+
H
+
→
M
n
2
+
+
S
O
2
−
4
+
H
2
O
(iv)
M
n
O
4
−
+
H
+
+
B
r
−
→
M
n
2
+
+
B
r
2
+
H
2
O
Q.
For the redox reaction
C
r
2
O
2
−
7
+
F
e
2
+
+
H
+
→
C
r
3
+
+
F
e
3
+
+
H
2
O
The correct coefficients of the following for the balanced reaction are
Q.
In the following redox reaction
C
r
2
O
2
−
7
+
F
e
2
+
→
F
e
3
+
+
C
r
3
+
One mole of
C
r
2
O
2
−
7
oxidises?
Q.
The oxidation half reaction for following reaction is
Fe
2+
(aq) + Cr
2
O
7
2-
(aq) → Fe
3+
(aq) + Cr
3+
(aq)
Q.
Write balanced half reactions for the following redox reaction:
C
r
2
O
2
−
7
+
F
e
2
+
→
C
r
3
+
+
F
e
3
+
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