$C r^{3 +}$ form four complexes with four different ligands which are $[C r (C l)_{6}]^{3 -}, [C r (H_{2} O)_{6}]^{3 +}, [C r (N H_{3})_{6}]^{3 +}$ and $[C r (C N)_{6}]^{3 -}$ . The order of CFSE $(Δ_{o})$ in these complexes is in the order :

[C r C l_{6}]^{3 -} = [C r (H_{2} O)_{6}]^{3 +} = [C r (N H_{3})_{6}]^{3 +} = [C r (C N)_{6}]^{3 -}

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[C r C l_{6}]^{3 -} < [C r (H_{2} O)_{6}]^{3 +} < [C r (N H_{3})_{6}]^{3 +} < [C r (C N)_{6}]^{3 -}

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[C r C l_{6}]^{3 -} > [C r (H_{2} O)_{6}]^{3 +} > [C r (N H_{3})_{6}]^{3 +} > [C r (C N)_{6}]^{3 -}

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[C r C l_{6}]^{3 -} < [C r (H_{2} O)_{6}]^{3 +} = [C r (N H_{3})_{6}]^{3 +} < [C r (C N)_{6}]^{3 -}

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Solution

The correct option is C $[C r C l_{6}]^{3 -} < [C r (H_{2} O)_{6}]^{3 +} < [C r (N H_{3})_{6}]^{3 +} < [C r (C N)_{6}]^{3 -}$
The order of CFSE $(Δ_{o})$ in these complexes is in the order $[C r C l_{6}]^{3 -} < [C r (H_{2} O)_{6}]^{3 +} < [C r (N H_{3})_{6}]^{3 +} < [C r (C N)_{6}]^{3 -}$ .
This is based on the relative positions of the ligands in the spectrochemical series which is based on the field strength as measured by experimental methods.

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Similar questions

Arrange the following complex ions in increasing order of crystal field splitting energy $△_{0} .$
$[C r (C l)_{6}]^{3 -}, [C r (C N)_{6}]^{3 -}, [C r (N H_{3})_{6}]^{3 +}$

The absorption maxima of some complexions are as follows:

$[C r C l_{6}]^{3 -} - 760 n m$

$[C r (N H_{3})_{6}]^{3 +} - 470 n m$

$[C r (H_{2} O)_{6}]^{3 +} - 695 n m$

The order of $Δ_{o}$ for these ions is

Q. Assertion :

Δ_{o}

increases in the order of

[C r C l_{6}]^{3 -} < [C r (C N)_{6}]^{3 -} < [C r (C_{2} O_{4})_{3}]^{3 -}

Reason: The stronger the ligand field, the higher will be

Δ_{o}

value.

Q. Predict the order of

Δ_{o}

for the following compounds:-
(i)

[C r (H_{2} O)_{6}]^{3 +}

(ii)

[C r (C N)_{2} (H_{2} O)_{4}]^{-}

(iii)

[C r (C N)_{4} (H_{2} O)_{2}]^{-}

(iv)

[C r (C N)_{6}]^{3 -}

Q. The hybridization of

C r

[C r (H_{2} O)_{6}]^{3 +}

ion and

[C r (C N)_{6}]^{3 -}

ion are respectively :

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Cr3+ form four complexes with four different ligands which are [Cr(Cl)6]3−,[Cr(H2O)6]3+,[Cr(NH3)6]3+ and [Cr(CN)6]3−. The order of CFSE (Δo) in these complexes is in the order :

$C r^{3 +}$ form four complexes with four different ligands which are $[C r (C l)_{6}]^{3 -}, [C r (H_{2} O)_{6}]^{3 +}, [C r (N H_{3})_{6}]^{3 +}$ and $[C r (C N)_{6}]^{3 -}$ . The order of CFSE $(Δ_{o})$ in these complexes is in the order :