Question

$\left[Cr\right(en{)}_3\left]\right[Ni\left(CN{)}_5\right]$ comprised of two types of complex ions; one is a complex of $Cr$(III) with ethylenediamine (en), having a coordination number of $6$ and the other is a complex of $Ni$(II) with $C{N}^{-}$ and having a coordination number of $5$.
If true enter 1, else enter 0

Answer 1

Given is the complex, $\left[Cr\right(en{)}_3\left]\right[Ni\left(CN{)}_5\right]$.

It consists of two types of complex ions.

One is a complex of $Cr\left(III\right)$, which is $\left[Cr\right(en{)}_3{]}^{3+}$. Here, $-en$ is a bidentate ligand and so, the coordination number of Cr is 6.

Other is a complex of $Ni\left(II\right)$, which is $\left[Ni\right(CN{)}_5{]}^{3-}$. Here, $-CN$ is a monodentate ligand and so, the coordination number of Ni is 5.

Hence, the statement is true.