$[C r (H_{2} O)_{6}] C l_{3}$ (at, no. of Cr = 24) has a magnetic moment of 3.83 B.M. The correct distribution of 3d electrons in the Chromium of the complex is :

3 d_{x y}^{1}, 3 d_{y z}^{1}, 3 d_{y z}^{1}

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(3 d_{x^{2} - y^{z}})^{1}, 3 d_{z^{2}}^{1}, 3 d_{x z}^{1}

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3 d_{x z}^{1}, (3 d_{x^{2} - y^{2}})^{1}, 3 d_{y z}^{1}

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3 d_{x y}^{1}, 3 d_{y z}^{1}, 3 d_{x z}^{1}

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Solution

The correct option is D $3 d_{x y}^{1}, 3 d_{y z}^{1}, 3 d_{x z}^{1}$
$[C r (H_{2} O)_{6}] C l_{3}$ (at, no. of $C r = 24$ ) has a magnetic moment of $3.83$ B.M. The correct distribution of $3 d$ electrons of chromium in the complex is $3 d_{x y}^{1}, 3 d_{y z}^{1}, 3 d_{x z}^{1}$ .
The magnetic moment of $3.83$ B.M corresponds to $3$ unpaired electrons.
$3.83 = \sqrt{n (n + 2)} n = 3$
All these electrons are present in $t_{2 g}$ orbitals. These correspond to $3 d_{x y}^{1}, 3 d_{y z}^{1}, 3 d_{x z}^{1}$ .

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