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Lanthanides Electronic Configuration

[CrH2O6]Cl3 a...

Question

$[C r (H_{2} O)_{6}] C l_{3}$ (atomic number of $C r = 24$ ) had a magnetic moment of $3.83 B . M .$ The correct distribution of $3d$electrons in the chromium present in the complex is :

3 d_{x y}^{1}, 3 d_{y z}^{1}, 3 d_{z x}^{1}

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3 d_{x y}^{1}, 3 d_{y z}^{1}, 3 d_{z^{2}}^{1}

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3 d_{(x^{2} - y^{2})}^{1}, 3 d_{z^{2}}^{1}, 3 d_{z x}^{1}

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3 d_{x y}^{1}, 3 d_{x^{2} - y^{2}}^{1}, 3 d_{x z}^{1}

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Solution

The correct option is A $3 d_{x y}^{1}, 3 d_{y z}^{1}, 3 d_{z x}^{1}$
$[C r (H_{2} O)_{6}] C l_{3}$
+3 n = 3
magnetic moment
$μ = \sqrt{n (n + 2)}$ B.M.
and in octahedral complex these three electron have $3 d_{x y}^{1}, 3 d_{y z}^{1}, 3 d_{z x}^{1}$ configuration

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Similar questions

[C r {(H_{2} O)}_{6}] C l_{3}

C r = 24

3.83 B . M

3 d

[C r (H_{2} O)_{6}] C l_{3}

[C r (H_{2} O)_{6}] C l_{3}

B . M .

3 d

C r

^{2}

^{2}

^{6}

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^{6}

^{1}

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^{3 +}

^{3 +}

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