Cr in CrO2Cl2 is present in + 6 oxidation state:
True
CrO2Cl2
Let x be the oxidation number of Cr.
Oxidation number of O and Cl are -2 and -1 respectively.
We apply the rules for assigning oxidation number:
x+2(−2)+2(−1)=0
x−4−2=0
Solving,x=+6