$C r (s) | C r^{3 +} | | F e^{2 +} | F e (s)$
In above cell, the value of $n$ in the Nernst equation:
i.e., $E = E^{\circ} - \frac{0.059}{n} {log}_{10} Q$ will be:

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Solution

The correct option is A 6
$C r (s) | C r^{3 +} | | F e^{2 +} | F e (s)$
$C r^{3 +} + 3 e^{-} ⟶ C r \times 2$
$F e_{(s)} ⟶ F e^{2 +} + 2 e^{-} \times 3$
$⟹ 2 C r^{3 +} + 2 F e_{(s)} ⟶ 2 C r + 3 F e^{2 +}$
$∴$ No. of $e^{-}$ transfered $= 6$

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