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Byju's Answer
Standard XII
Chemistry
Preparation of Carboxylic Acids
(Cr2O7 2-). +...
Question
(Cr2O7 2-). + (2I-) + (14H+) —> (I2-) + (2Cr3+) + (7H2O) which are not in balanced position?
(a) H+ & H2O.
(b)Cr2O7 2- & Cr3+
(c) I- & I2.
(d) all are balanced
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Solution
The balanced equation is
Cr
2
O
7
2-
. + 6I
-
+ 14H
+
→
6I
2
+ 2Cr
3
+
+ 7H
2
O
​Answer is option c
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Similar questions
Q.
Given a reaction:
C
r
2
O
2
−
7
+
F
e
2
+
+
H
⊕
⟶
C
r
3
+
+
F
e
3
+
+
H
2
O
The balanced equation is
6
F
e
2
+
+
14
H
⊕
+
C
r
2
O
2
−
7
⟶
6
F
e
3
+
+
2
C
r
3
+
+
7
H
2
O
.
If true enter 1, else enter 0.
Q.
Balance the following equations:
C
r
2
O
2
−
7
+
I
−
+
H
+
→
C
r
3
+
+
I
2
+
H
2
O
Q.
To balance H in Cr
2
O
7
2-
(aq)
→ Cr
3+
(aq)
+ 7H
2
O (in acidic medium), we will
Q.
Balance the following equations by ion electron method.
C
r
2
O
7
2
−
+
I
−
+
H
+
→
C
r
3
+
+
I
2
+
H
2
O
.
Q.
Balance the following equations by oxidation number method.
C
r
2
O
7
2
−
+
I
−
+
H
+
→
C
r
3
+
+
I
2
+
H
2
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