Cracking of Ethane gives a mixture of

Ethene and H₂

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Ethene, Methane and H₂

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H2 and methane

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Only CH4

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Solution

The correct option is B
Ethene, Methane and H₂

$C H_{3} C H_{3} ⟶ 2 \cdot C H_{3} (i n i t i a t i o n)$

$C H_{3} C H_{3} + \cdot C H_{3} ⟶ C H_{4} + C H_{3} \cdot C H_{2} (m e t h a n e)$

Radical decomposition:

$C H_{3} \cdot C H_{2} ⟶ C H_{2} = C H_{2} + \cdot H (E t h e n e)$

$\cdot H + \cdot H ⟶ H_{2} (H y d r o g e n)$

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