Cris also participated in the stack race and he covers exactly a length of $2$ ft with each jump. He completed the race in $39$ jumps. Find the distance covered by him (in yards) to complete the race.

26

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25

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78

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39

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Solution

The correct option is A $26$
Distance covered in one jump $= 2$ ft
So, distance covered in $39$ jumps
$= 39 \times 2$
$= 78$ ft

Note: $1 yard = 3 ft$

$1 ft = \frac{1}{3} yard$

$\Rightarrow 78 ft = \frac{78}{3} = 26 yard$
Therefore, distance covered is $26$ yards.

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Cris also participated in the stack race and he covers exactly a length of 2 ft with each jump. He completed the race in 39 jumps. Find the distance covered by him (in yards) to complete the race.

The correct option is A 26Distance covered in one jump =2 ft So, distance covered in 39 jumps =39×2 =78 ft Note: 1 yard=3 ft 1 ft=13 yard ⇒78 ft=783=26 yard Therefore, distance covered is 26 yards.

Cris also participated in the stack race and he covers exactly a length of $2$ ft with each jump. He completed the race in $39$ jumps. Find the distance covered by him (in yards) to complete the race.

The correct option is A $26$
Distance covered in one jump $= 2$ ft
So, distance covered in $39$ jumps
$= 39 \times 2$
$= 78$ ft

Note: $1 yard = 3 ft$

$1 ft = \frac{1}{3} yard$

$\Rightarrow 78 ft = \frac{78}{3} = 26 yard$
Therefore, distance covered is $26$ yards.