Question

Critical angle for certain medium is $si{n}^{-1}\left(0.6\right)$. The polarizing angle of that medium is :

• A. $ta{n}^{-1}\left(1.5\right)$
• B. $ta{n}^{-1}\left(0.8\right)$
• C. $ta{n}^{-1}\left(1.6667\right)$
• D. $ta{n}^{-1}\left(0.667\right)$

Answer 1

The correct option is C $ta{n}^{-1}\left(1.6667\right)$

Critical angle $C=si{n}^{-1}\left(0.6\right)$
$Sin\left(C\right)=0.6$
$\mu =\frac{1}{sinC}=\frac{1}{0.6}$
Polarising angle $i_p=ta{n}^{-1}\left(\mu \right)$
$=ta{n}^{-1}\left(\frac{1}{0.6}\right)$
$=ta{n}^{-1}\left(1.6667\right)$