Question

Critical density of a gas having molecular weight $39g$ ${mol}^{-1}$ is $0.1\times {10}^{3}g{cm}^{-3}$. Its critical volume in $L$ ${mol}^{-1}$ is:

• A. $0.390$
• B. $3.90$
• C. $0.039$
• D. $39.0$
• E. $390$

Answer 1

The correct option is A $0.390$

Given,
Critical density $=0.1\times {10}^{3}g{cm}^{-3}$

Critical mass $=$ molecular weight $=39g$

$\because$ Critical density $=\frac{\text{Critical mass}}{\text{Critical volume}}$

$\therefore$ Critical volume $\left(inL{mol}^{-1}\right)=\frac{\text{Critical mass}}{\text{Critical density}}=\frac{39}{0.1\times {10}^3}$

$=0.390L{mol}^{-1}$

Hence, the correct option is $\text{A}$