Question

# Critical temperature for $$CO_2$$ and methene are $$31.1^0$$ C and $$-81.9^0$$ C respectively. Which of these has stronger intermolecular forces and why?

Solution

## Critical temperature $${T_c} = \frac{{8a}}{{27Rb}}$$As, we know that higher the value of $$'a'$$ stronger the intermolecuarforces.In the above formula $${T_c} \propto a$$,          $${T_c} \propto \frac{1}{b}$$Therefore higher value of critical temperature gives greater value of $$'a'$$, i.estronger intermolecualr forces of attraction.$$\therefore \,\,C{O_2}$$ has stronger intermolecular forces of attraction.Chemistry

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