Question

Critical temperature of $H_{2}O$ is greater than that of $O_2$ because $H_{2}O$ molecules have:

• A. greater dipole moment
• B. V-shape
• C. lesser number of electrons
• D. it has only sigma bonds

Answer 1

The correct option is A greater dipole moment

Critical temperature of $H_{2}O$ is greater than that of $O_2$ because $H_{2}O$ molecules have a greater dipole moment.

Greater dipole moment corresponds to stronger inter-molecular attractive forces. Due to this, $H_{2}O$ vapour can be liquefied at higher temperature than $O_2$ gas.