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Compounds of Xenon

CrO5 reacts w...

Question

$C r O_{5}$ reacts with $H_{2} S O_{4}$ to give $C r_{2} {(S O_{4})}_{3}$ , $H_{2} O$ and $O_{2}$ . Moles of $O_{2}$ liberated by $1$ mole of $C r O_{5}$ in this reaction is (as nearest integer) :

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Solution

The balanced reaction is as follows:
$4 C r O_{5} + 6 H_{2} S O_{4} \to 2 C r_{2} (S O_{4})_{3} + 7 O_{2} + 6 H_{2} O$
So, $O_{2}$ produced by one mole of $C r O_{5} = \frac{7}{4} = 1.75$
Therefore, the nearest integer is $2$ .

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