Question

Cross section of a glass prism has the form of an equilateral triangle. A ray is incident onto one of the faces perpendicular to it. Angle $\theta$ between the incident ray and the ray that leaves the prism in degree is $\times {60}^{\circ }$. The refraction index of glass is 1.5.

Answer 1

$1.5\times sin\times {60}^{\circ }=1\times sinr$

$1.5\times \frac{\sqrt{3}}{2}=sinr$

$\frac{15}{10}\times \frac{\sqrt{3}}{2}=sinr$

$\frac{3\sqrt{3}}{4}=sinr$

$sinr>1$

$\therefore$ T/R will take place angle = ${120}^{\circ }$