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Standard IX

Chemistry

Preparation of Hydrogen from Cold Water and Metals

Cs reacts wit...

Question

Cs reacts with chlorine to form:

CsCl₂

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CsCl₃

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CsCl

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Cs₂Cl₂

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Solution

The correct option is C
CsCl

Alkali metals readily reacts with halogens to form ionic haides.

2Cs + Cl → 2 CsCl

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Similar questions

Q. Caesium chloride is formed according to the following equation:

C s (s) + 0.5 {C l}_{2} (g) ⟶ C s C l (s)

The enthalpy of sublimation of

C s

, enthalpy of dissociation of chlorine, ionization energy of

C s

and electron affinity of chlorine are

81.2, 243.0, 375.7

and

- 348.3 k J

{o l}^{- 1}

. The energy change involved in the formation of

C s C l

388.6 k J . {m o l}^{- 1}

. Calculate the lattice energy of

C s C l

Q. Cesium chlorides is formed according to the following equation

C s (s) + 0.5 C l_{2} (g) \to C s C l (s)

. The enthalpy of sublimation of Cs, the enthalpy of dissociation of chlorine, ionization energy of

C s

and electron affinity of cholrine are

81.2, 243.0, 375.7

and

- 348.3 k J m o l^{- 1}

. The energy involved in the formation of

C s C l

- 388.6 k J m o l^{- 1}

. Calculate the lattice energy of

C s C l

Q. Caesium chlorides is formed according to the following equation

C s (s) + 0.5 C l_{2} (g) \to C s C k (s)

. The enthalpy of sublimation of

C s

, enthalpy of dissociation of chlorine, ionization energy of

C s

and electron affinity of chlorine are

81.2, 243.0, 375.7

and

- 348.3 k J m o l^{- 1}

. The energy change involved in the formation of

C s C l

- 388.6 K J m o l^{- 1}

. Calculate the lattice energy of

C s C l

In solid CsCl each Cl is closely packed with how many Cs

Q. Assertion :

C s C l

has body-centered cubic arrangement. Reason:

C s C l

has one

C s^{+}

ion and

8 C l^{-}

ions in its unit cell.

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Cs reacts with chlorine to form:

The correct option is C CsCl Alkali metals readily reacts with halogens to form ionic haides. 2Cs + Cl → 2 CsCl

The correct option is C
CsCl

Alkali metals readily reacts with halogens to form ionic haides.

2Cs + Cl → 2 CsCl