MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Mole Concept

CsBr crystall...

Question

CsBr crystallises in a body centred cubic lattice. Theunit cell length is 436.6 pm. Given that the atomicmass of Cs-133 and that of Br-80 amu andAvogadro number being 6.023 x 1023 mol-1 thedensity of CsBr is:(1) 42.5 g cm-3(3) 8.25 g cm 3(2) 0.425 g cm-3(4) 4.25 g cm-3

Open in App

Solution

Suggest Corrections

thumbs-up

3

Similar questions

C s B r

crystallises in a body centred cubic lattice. The unit cell length is

436.6 p m

. Given that the atomic mass of

C s = 133

B r = 80

) amu and Avogadro number being

6.02 \times 10^{23}

m o l^{- 1}

, the density of

C s B r

Q. CsBr crystallizes in a body-centred cubic lattice of unit cell edge length

436.6

pm. Atomic masses of Cs and Br are

133

80

amu respectively. The density (in g cm

^{- 3}

Q. CsBr crystallizes in a body-centered cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being

6.02 \times 10^{23}

^{- 1}

, the density of CsBr is:

C s B r

crystals are formed with bcc crystal lattice where

B r^{-}

occupies the corners and

C s^{+}

occupies the centre of the cube with a unit cell length of nearly

400 p m

. What will be density of

C s B r

?
Given molecular mass of CsBr is 213 g/mol and

N_{A} = 6 \times 10^{23}

Q. An element crystallising in body centred cubic lattice has an edge length of

500 p m

. If density is

4 g c m^{- 3},

the atomic mass of the element

(i n g m o l^{- 1})

N_{A} = 6 \times 10^{23}

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Mole Concept

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard X Chemistry

Join BYJU'S Learning Program

CrossIcon