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Question

CsBr has a bcc type structure with edge length 4.3 pm. The shortest inter ionic distance between Cs+ and Br− is:

A
3.72 pm
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B
1.86 pm
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C
7.44 pm
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D
4.3 pm
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Solution

The correct option is A 3.72 pm
CsBr has a bcc type structure. Here Cs+ ion are present at the body centre of the cube and Br ions are present at the corners of the cube. So the relation between inter ionic distance (r++r) and edge length will be
3a=2(r++r)
Shortest distance would be r++r
Here, r++r=3a2=1.73×4.32=3.7195 pm3.72 pm

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