csBr has cubic in diamond carbon atom occupy fcc lattice points as well as alternate tetrahedral voids . if edge length of the unit cell is 3.56pm , then find radious of carbon atom

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Q. In diamond, carbon atom occupy FCC lattice points as well as alternate tetrahedral voids. If edge length of the unit cell is

356

pm, then the radius (in pm) of carbon atom is:

In diamond, carbon atom occupy FCC lattice points as well as alternate tetrahedral voids. If edge length of the unit cell is 356 pm, then radius of carbon atom is

Q. If in diamond, there is unit cell of carbon atoms as fcc and if carbon atom is

s p^{3}

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In which of the following structures coordination number for cations and anions in the packed structure will be same ?

(a) $C l^{-}$ ions form fcc lattice and $N a^{+}$ ions occupy all octahedral voids of the unit cell

(b) $C a^{2 +}$ ions form fcc lattice and $F^{-}$ ions occupy all the eight tetrahedral voids of the unit cell

(d) $S^{2 -}$ ions form fcc lattice and $Z n^{2 +}$ ions go into alternate tetrahedral voids of the unit cell

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