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Question

(cscAsinA)(secAcosA)=1tanA+cotA

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Solution

L.H.S
(cosecAsinA)(secAcosA)
=(1sinAsinA)(1cosAcosA)
=(1sin2AsinA)(1cos2AcosA)
cos2Asin2AsinAcosA
=sinAcosA
R.H.S.
=1tanA+cotA
=1sinAcosA+cosAsinA
=1sin2A+cos2AsinAcosA
=sinAcosA
Thus, L.H.S=R.H.S.

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