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Lewis Kossel Structure

CsCl crystall...

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CsCl crystallize in cubic cell that has Cl ion at corners and Cs ion at the centre.if radius of anion is 1.81 angstrom and of cation is 1.69 angstrom , then find the edge length

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Q. If the length of the body diagonal for CsCl which crystallizes into a cubic structure with

C l^{-}

ions at the corners and

C s^{+}

ions at the centre of the unit cells is

7 ˚ A

and the radius of the

C s^{+}

1.69 ˚ A

, what is the radius of

C l^{-}

˚ A

?

C s C l

crystallizes in a cubic lattice that has a

C l^{-}

at each corner and

C s^{+}

at the centre of the unit cell. If

(r_{C s^{+}}) = 1.69 o A

(r_{C l^{-}}) = 1.81 o A

, what is the value of edge length a of the cube?

Q. If the length of body diagonal for

CsCl

, which crystallises into a cubic structure with

{Cl}^{-}

ions at the corners and

{Cs}^{+}

ions at the centre of unit cell is

7 ˚ A

and the radius of

{Cs}^{+}

1.69 ˚ A

. The radius of

{Cl}^{-}

Q. If the length of the body diagonal for CsCl which crystallises into a cubic structure with

C l^{-}

ions at the corners and

C s^{+}

ions at the centre of the unit cells is

7 ˚ A

and the radius of the

C s^{+}

1.69 ˚ A

. What is the radii (in

˚ A

C l^{-}

If the radius of Mg2+ ion, Cs+ ion, O2- ion, S2- ion and Cl- ion are 0.65 Å , 1.69 Å, 1.40 Å, 1.84 Å, and 1.81 Å respectively. Then the co-ordination numbers of the cations in the crystals of MgS, MgO and CsCl respectively are:

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