[Cu(NH3)4]2+ and [Cu(CN)4]2− are labile complexes.
A
True
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B
False
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Solution
The correct option is A True Transition metal complexes which undergo rapid substitution of one ligand for another are labile. The four-coordinated complexes of Cu2+ are labile so [Cu(NH3)4]2+ and [Cu(CN)4]2− are labile complexes.