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Question

[Cu(NH3)4]2+ and [Cu(CN)4]2− are labile complexes.

A
True
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B
False
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Solution

The correct option is A True
Transition metal complexes which undergo rapid substitution of one ligand for another are labile.
The four-coordinated complexes of Cu2+ are labile so
[Cu(NH3)4]2+ and [Cu(CN)4]2 are labile complexes.

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