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Question

[Cu(NH3)4]2+ shows the following hybridization

A
dsp2
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B
sp3d
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C
dsp3
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D
sp3
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Solution

The correct option is A dsp2
Cu=[Ar]3d104s1
Cu2+=[Ar]3d9

The electron pair donate by NH3 enters into 4s,4p and one 3d subshell of Cu to form dsp2 hybrid orbital.

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