$C u {S O}_{4} \cdot 5 H_{2} O$ is blue in colour whereas anhydrous $C u {S O}_{4}$ is colourless. Why?

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Solution

Hydrated copper sulphate $C u S O_{4} \cdot 5 H_{2} O$ is blue in colour. The ligand (water) molecules causes splitting of d orbitals. This facilitates d-d transition and colour.
Anhydrous copper sulphate $C u S O_{4}$ is colourless. In the absence of ligand (water) molecules, splitting of d orbitals is not possible. Hence, d-d transition is not possible.

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$C u S O_{4} .5 H_{2} O$ is blue in colour while $C u S O_{4}$ is colourless. Why?

C u S O_{4} \cdot 5 H_{2} O

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(C u S O_{4} \cdot 5 H_{2} O)

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