The correct option is B ( 1 / 64) = #160;( 1 / 4 #160;) ^ 3 =(1/4)(1/4)(1/4)= 1 / 64 ...

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Cube-Root of Fractional Numbers

Cube of 1 ...

Question

Cube of $(\frac{1}{4})$ is -

(\frac{1}{64})

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(\frac{1}{16})

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- (\frac{1}{64})

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- (\frac{1}{16})

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Solution

The correct option is B $(\frac{1}{64})$
$= {(\frac{1}{4})}^{3} = (\frac{1}{4}) (\frac{1}{4}) (\frac{1}{4}) = \frac{1}{64}$

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Similar questions

64 c m^{3}

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1 + \frac{1}{4} + \frac{1}{16} + \frac{1}{64} + \frac{1}{256} + . . . . ?

1 + \frac{1}{4} + \frac{1}{9} + \frac{1}{16} + . . . = \frac{π^{2}}{6}

\frac{1}{4} + \frac{1}{16} + \frac{1}{36} + \frac{1}{64} + . . .

1 + \frac{1}{4 \times 2!} + \frac{1}{16 \times 4!} + \frac{1}{64 \times 6!} + . . . . \infty

1 + \frac{1}{4 \cdot 2!} + \frac{1}{16 \cdot 4!} + \frac{1}{64 \cdot 6!} + \dots \infty

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