Question

Cube root of (7 x 7 x 7) is

Answer 1

Cube root of $(7\times 7\times 7)$ is $(7\times 7\times 7{)}^{\frac{1}{3}}$
$(7\times 7\times 7{)}^{\frac{1}{3}}=(7^3{)}^{\frac{1}{3}}$ $=7^{3\times \frac{1}{3}}=7^{\frac{3}{3}}=7^1$
$\therefore$ Cube root of $(7\times 7\times 7)$ is 7.