Cube root of 700249*5

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Solution

Hi,

$\sqrt[3]{700 \times 2 \times 49 \times 5} = \sqrt[3]{7 \times 2 \times 2 \times 5 \times 5 \times 2 \times 7 \times 7 \times 5} = \sqrt[3]{7 \times 7 \times 7 \times 2 \times 2 \times 2 \times 5 \times 5 \times 5} = 2 \times 5 \times 7 = 70$
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49 \times 56

Find the cube-roots of :

(i) $700 \times 2 \times 49 \times 5$ (ii) $- 216 \times 1728$ (iii) $- 64 \times - 125$

(iv) $- \frac{27}{343}$ (v) $\frac{729}{- 1331}$ (vi) 250.047 (vii) -175616

1, ω, ω^{2}

(2 - ω) (2 - ω^{2}) (2 - ω^{10}) (2 - ω^{11}) = 49

If 1000 = 2 × 2 × 2 × 5 × 5 × 5 then cube root of 1000 is:

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