$C u C l$ is sparingly soluble in water, but it dissolves in $K C l$ solution due to the formation of:

K_{3} [C u C l_{4}]

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K_{2} [C u C l_{4}]

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K [C u C l_{2}]

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K_{2} [C u C l_{2}]

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Solution

The correct option is A $K_{3} [C u C l_{4}]$
$C u C l$ dissolves in $K C l$ due to the formation of $K_{3} [C u C l_{4}]$ complex ion.

The $[C u C l_{4}]^{3 -}$ ion is an exceptionally stable ion and the formation of this ion is the driving force of the reaction.

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Similar questions

C u {C l}_{2}

{[C u {(H_{2} O)}_{4}]}^{2 +}

{[{C u C l}_{4}]}^{2 -}

K C l, C u C l, C u {C l}_{2}

[N^{+} (M e)_{4}] [C u C l_{4}] [C u C l_{4}]

[N^{+} (H)_{4}] [C u C l_{4}]

13.44 g

C u C l_{2}

1 k g

C u C l_{2}

K_{b} = 0.52 K k g m o l^{- 1}

C u C l_{2} = 134.4 g / m o l

A l F_{3}

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