CuIs-e- - Cus-I- EoCu-Cu- -0-16 V Zn2-aq-2e- - Zns- EoZn2-Zn-0-76 VCalculate the EMF-

The correct option is C 0.60 V CuI(s)+e^ → Cu(s)+I^ ; E^o_Cu^+/Cu= 0.16 V Zn^2+(aq)+2e^ → Zn(s); E^o_Zn^2+/Zn= 0.76 V EMF of the cell ...

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Byju's Answer

Standard XII

Chemistry

Representation of Cell

CuIs+e- → Cus...

Question

$C u I (s) + e^{-} \to C u (s) + I^{-};$ $E_{C u^{+} / C u}^{o} = - 0.16 V$
$Z n^{2 +} (a q) + 2 e^{-} \to Z n (s);$ $E_{Z n^{2 +} / Z n}^{o} = - 0.76 V$

Calculate the EMF.

0.90 V

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0.45 V

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0.60 V

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0.75 V

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Solution

The correct option is C 0.60 V
$C u I (s) + e^{-} \to C u (s) + I^{-};$
$E_{C}^{o} u^{+} / C u = - 0.16 V$

$Z n^{2 +} (a q) + 2 e^{-} \to Z n (s);$
$E_{Z n^{2 + / Z n}}^{o} = - 0.76 V$

EMF of the cell $= E_{c a t h o d e (R P)}^{o} - E_{a n o d e (R P)}^{o}$
$= - 0.16 - (- 0.76) = 0.60 V$

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Similar questions

Q. Calculate

E_{C e l l}^{o}

value of the following reactions:

Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)

[Given:

E_{C u^{2 +} / C u}^{\circ} = 0.34 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

]

Q. Calculate

E^{\circ}

values of following reactions:

C u_{(s)} + Z n_{(a q)}^{2 +} \to Z n_{(s)} + C u_{(a q)}^{2 +}

[Given:

E_{C u^{2 +} / C u}^{0} = 0.34 V, E_{Z n^{2 +} / Z n}^{0} = - 0.76 V

]

Z n (s) / Z n^{2 +} (a q) ∥ C u^{2 +} (a q) / C u (s)

{E^{0}}_{{Z n}^{2 +} / Z n} =

-

0.76V,

{E^{0}}_{{C u}^{2 +} / C u} =

+

0.34V.

Calculate

{E^{0}}_{c e l l}

and equilibrium constant

K

Q. Consider the cell,

Z n | Z n^{2 +} (a q) (1.0 M) | | C u^{2 +} (a q) (1.0 M) | C u

The standard reduction potentials are

+ 0.35 V

for

2 e^{-} + C u^{2 +} (a q) \to C u^{2 +} (a q) (1.0 M) | C u

The standard reduction potentials are

+ 0.35 V

for

2 e^{-} + C u^{2 +} (a q) \to C u

and

- 0.763 V

for

2 e^{-} + Z n^{2 +} (a q) \to Z n

Calculate the emf of the cell and tell whether the cell reaction spontaneous or not ?

Q. For the cell :

Z n | Z n^{2 +} | | C u^{2 +} | C u

E_{z n}^{⊖} = 0.736 V; E_{(c u)}^{⊖} = - 0.35 V

Calculate the cell EMF.

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CuI(s)+e−→Cu(s)+I−;EoCu+/Cu=−0.16V Zn2+(aq)+2e−→Zn(s); EoZn2+/Zn=−0.76VCalculate the EMF.

The correct option is C 0.60 VCuI(s)+e−→Cu(s)+I−;EoCu+/Cu=−0.16VZn2+(aq)+2e−→Zn(s);EoZn2+/Zn=−0.76VEMF of the cell =Eocathode(RP)−Eoanode(RP)=−0.16−(−0.76)=0.60V

$C u I (s) + e^{-} \to C u (s) + I^{-};$ $E_{C u^{+} / C u}^{o} = - 0.16 V$
$Z n^{2 +} (a q) + 2 e^{-} \to Z n (s);$ $E_{Z n^{2 +} / Z n}^{o} = - 0.76 V$

Calculate the EMF.

The correct option is C 0.60 V
$C u I (s) + e^{-} \to C u (s) + I^{-};$
$E_{C}^{o} u^{+} / C u = - 0.16 V$

$Z n^{2 +} (a q) + 2 e^{-} \to Z n (s);$
$E_{Z n^{2 + / Z n}}^{o} = - 0.76 V$

EMF of the cell $= E_{c a t h o d e (R P)}^{o} - E_{a n o d e (R P)}^{o}$
$= - 0.16 - (- 0.76) = 0.60 V$