Current flowing in a circuit having resistance of 30 W and an inductance of 0-4 - - H connected to an A-C- supply of 100 V and 50 Hz in series isA- 2 AB- 5 AC- 7 AD- none of these

The correct option is A 2A R=30Ω X_L=2π fL =2 ×π× 50×0.4/π =40Ω Z=√(R^2+X_L^2) =√(30^2+40^2) =50Ω l_rms=V_rms/Z =100/50 =2A ...

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Byju's Answer

Standard XII

Physics

Power in an AC Circuit

Current flowi...

Question

Current flowing in a circuit having resistance of 30 W and an inductance of (0.4/ $π$ ) H connected to an A.C. supply of 100 V and 50 Hz in series is

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none of these

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Solution

The correct option is A
2A

$R = 30 Ω X_{L} = 2 π f L = 2 \times π \times 50 \times \frac{0.4}{π} = 40 Ω Z = \sqrt{R^{2} + X_{L}^{2}} = \sqrt{30^{2} + 40^{2}} = 50 Ω l_{r m s} = \frac{V_{r m s}}{Z} = \frac{100}{50} = 2 A$

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Current flowing in a circuit having resistance of 30 W and an inductance of (0.4/ π ) H connected to an A.C. supply of 100 V and 50 Hz in series is

The correct option is A 2A R=30ΩXL=2πfL=2×π×50×0.4π=40ΩZ=√R2+X2L=√302+402=50Ωlrms=VrmsZ=10050=2A

Current flowing in a circuit having resistance of 30 W and an inductance of (0.4/ $π$ ) H connected to an A.C. supply of 100 V and 50 Hz in series is

The correct option is A
2A

$R = 30 Ω X_{L} = 2 π f L = 2 \times π \times 50 \times \frac{0.4}{π} = 40 Ω Z = \sqrt{R^{2} + X_{L}^{2}} = \sqrt{30^{2} + 40^{2}} = 50 Ω l_{r m s} = \frac{V_{r m s}}{Z} = \frac{100}{50} = 2 A$