Current gain in common base configuration is less than 1 because

I_{e} < I_{b}

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I_{b} < I_{e}

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I_{c} < I_{e}

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I_{e} < I_{c}

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Solution

The correct option is C $I_{c} < I_{e}$
$\propto= \frac{I_{c}}{I_{e}} < 1$ or $I_{c} < I_{e}$

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For a common base configuration of PNP transistor, the gain $(α)$ is 0.98, then current gain of common emitter configuration will be

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\frac{^{l_{C}}}{l_{E}} = 0.98

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