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Question

Current i flows through a long conducting wire bent at right angle as shown in figure. The magnetic field at a point P on the right bisector of the angle XOY at a distance r from O is



Your Answer
A
μ0iπr
 
Your Answer
B
2μ0iπr
 
Your Answer
C
μ0i4πr(2+1)
 
Correct Answer
D
μ04π.2ir(2+1)

Solution

The correct option is C μ04π.2ir(2+1)
By using B=μ04π.id(sinϕ1+sinϕ2), from figure d=r sin45=r2
Magnetic field due to each wire at P B=μ04π.i(r/2)(sin45+sin90)
=μ04π.ir(2+1)
Hence net magnetic field at P Bnet=2×μ04π.ir(2+1)

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