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Question

Current ‘I’ in the given branch of circuit is

A
1A
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B
2A
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C
3A
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D
4A
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Solution

The correct option is C 3A

i1=30.75=2.25Ai2=0.750.25=0.5Ai=i1+i2+0.25=2.25+0.5+0.25i=3A

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