Question

Current i is being driven through a cell of emf E and internal resistance r, as shown :

• A. the cell absorbs energy at the rate of Ei
• B. the cell stores chemical energy at the rate of $(Ei-i^{2}r)$
• C. the potential difference across the cell is E+ir
• D. some heat is produced in the cell

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A the cell absorbs energy at the rate of Ei
B the cell stores chemical energy at the rate of $(Ei-i^{2}r)$
C the potential difference across the cell is E+ir
D some heat is produced in the cell

Let Voltage drop across the terminals of the cell be $V$.
From kirchhoff's voltage law and ohm's law: $V=\epsilon +ir$
So, the power loss across the cell $=iV$
$=i\epsilon +i^{2}r$
where, $i^{2}r$ is the heat generated across the internal resitance , that is heat produced in the cell.
And $i\epsilon$ is the rate of energy stored as chemical energy.