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Self Induction

Current in a ...

Question

Current in a circuit fall from $5.0$ A to zero in $0.1$ S. If an average emf of $100$ Volt is induced then calculate self-inductance of a inductor in the circuit.

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Solution

Induced emf in an inductor is given as
$E M F_{i n d} = L \frac{d i}{d t}$
$⟹ 100 = L (\frac{5}{0.1})$
$⟹ L = 2 H$

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