Current in a coil of self-inductance 2.0H is increasing as i=2sint2. The amount of energy spent during the period when the current changes from 0 to 2A is:
Given that,
Self-inductance of coil = 2.0H
Let the current flowing through the coil be 2A at time t2
Now,
2=2sint2
t=√π2
Now, the amount of energy spent during the period when the current changes from 0 to 2 A
Now, Self-induced e. m. f
E=Ldidt
Now, the work done is
dW=L(didt)dq
dW=L×didt×idt
dW=Lidi
Now, on integrate
∫dW=t∫0Lidi
W=t∫0L2sint2d(2sint2)
W=t∫08Lsint2cost2tdt
W=4Lt∫0sin2t2dt
Now, let
θ=2t2
dθ=4tdt
dt=dθ4t
Now, put the value of 2t2and dt
W=4Lt∫0sinθdθ4
W=L[(−cosθ)]t0
W=−L[cos2t2]t0
W=−L[cos2t2]√π20
W=2L
W=2×2
W=4J
Hence, the amount of energy is 4 J