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Question

Current in a coil of self-inductance 2.0H is increasing as i=2sint2. The amount of energy spent during the period when the current changes from 0 to 2A is:

A
1 J
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B
2 J
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C
3 J
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D
4 J
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Solution

The correct option is D 4 J

Given that,

Self-inductance of coil = 2.0H

Let the current flowing through the coil be 2A at time t2

Now,

2=2sint2

t=π2

Now, the amount of energy spent during the period when the current changes from 0 to 2 A

Now, Self-induced e. m. f

E=Ldidt

Now, the work done is

dW=L(didt)dq

dW=L×didt×idt

dW=Lidi

Now, on integrate

dW=t0Lidi

W=t0L2sint2d(2sint2)

W=t08Lsint2cost2tdt

W=4Lt0sin2t2dt

Now, let

θ=2t2

dθ=4tdt

dt=dθ4t

Now, put the value of 2t2and dt

W=4Lt0sinθdθ4

W=L[(cosθ)]t0

W=L[cos2t2]t0

W=L[cos2t2]π20

W=2L

W=2×2

W=4J

Hence, the amount of energy is 4 J


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