The correct option is C If voltage applied is V=Vmsinωt, then the circuit may be containing resistance and capacitance only
I=3sinωt+4cosωt
⇒I=5(35sinωt+45cosωt)
⇒I=5sin(ωt+α) ;α=tan−145
therefore,
rms value of current = 5/√2A
Mean value of current one half period = 1π∫π05sinθdθ=1π5|−cosθ|π0=10πA
The current lags the voltage by an angle θ, therefore the circuit may contain resistance and capacitor only.