Question

Current in the inductor is $0.8\text{A}$ while that in the capacitor is $0.6\text{A}$. The current drawn from the source is $P\times {10}^{-1}\text{A}$. Then, find the value of $P$.

Answer 1

Since inductor and capacitor are connected in parallel, voltage across both will be in phase.
Current lags voltage by $\pi /2$ in the inductor and leads by $\pi /2$ in capacitor.

Hence, $I_{\text{net}}=I_L-I_C$
$=0.8-0.6=0.2\text{A}$ is the current drawn from the source.
$\therefore P=2$