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Byju's Answer

Standard XII

Physics

Galvanometer

Current sensi...

Question

Current sensitivity of a moving coil galvanometer is $5$ div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is $20$ div/V. The resistance of the galvanometer is?

250

Ω

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40

Ω

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500

Ω

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25

Ω

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Solution

The correct option is D $250$ $Ω$
Current sensitivity

$I_{g} = \frac{N B A}{K} = \frac{5 d i v}{m A} = 5000 \frac{d i v}{A}$

Voltage sensitivity $v_{s} = \frac{N B A}{K R} = 20 \frac{d i v}{v}$

$\Rightarrow \frac{I_{g}}{v_{s}} = R$

$\Rightarrow R = \frac{5000}{20} = 250 Ω$

Option 1 is correct.

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Current sensitivity of a moving coil galvanometer is 5 div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/V. The resistance of the galvanometer is?

The correct option is D 250 ΩCurrent sensitivity Ig=NBAK=5divmA=5000divA Voltage sensitivity vs=NBAKR=20divv ⇒Igvs=R ⇒R=500020=250Ω Option 1 is correct.

Current sensitivity of a moving coil galvanometer is $5$ div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is $20$ div/V. The resistance of the galvanometer is?