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B
0.02A
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C
0.03A
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D
0.04A
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Solution
The correct option is B0.02A Let, D1 be the diode in series with 50Ω resistance, D2 be the diode in series with 150Ω resistance. Diode D1 is reversed biased and have infinite resistance hence no current will flow through 50Ω resistance. Thus, total current in the circuit is I=6150+50+100
I=0.02A
As all the resistances are in series, thus we get the current passing through the 100 ohm resistor as 0.02A.